Quote:
Originally Posted by sokdo
I remember there was an easy way or a short cut method of figuring this out but I just can't remember, maybe some of you guys can remember back to your high school days?
So solve this equation:
(5/((x+1)^1)+(5/((x+1)^2)+(5/((x+1)^3).....+(5/((x+1)^60) = 50
find X
Wasn't there a shortcut method to solving this really easily? Its like on the tip of my tongue and it's driving me insane lol
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You might be thinking of the fact that in geometric series' (meaning the ratio between elements is constant) of the following type:
1 + 1/(n^1) + 1/(n^2) + 1/(n^3) ... 1/n^N = 1 / ( 1 - ( 1 / n))
i.e.
1 + 1/2 + 1/4 + 1/8 + 1/16 + ... = 1 / (1 - ( 1 / 2 )) = 2
I'm just taking a stab at what you're looking for/remembering. The series you posted terminates, so I'm not sure what you're looking for.